a solution is prepared by dissolving 4.87 g of sodium dichromate in 25.0 ml of water
a solution is prepared by dissolving 4.87 g of sodium dichromate in 25.0 ml of water. (d=1.00g/mL).calculate a. the mass percent of sodium dichromate in the solution. b. the mass percent o water in the solution. c the mole fraction of sodium dichromate in the solution.
How much of this do you know how to do? Show as much as you can do and I can help from there.
well mass percent is mass solute divided by total mass solution times 100..so would it be..25.0/4.87 x 100?
Your formula is ok. Your use of it is not. [mass solute/total mass]x100= 4.87 g Na2Cr2O7 is the solute. Total mass = 4.87 + 25 = ?? You do the math.
b) Solvent is water so mass percent H2O = mass H2O (25 g)/total mass total mass still 4.87 + 25 = ?? You do the math.
c) mol fraction Na2Cr2O7 = mols Na2Cr2O7/total mols.
mol Na2Cr2O7 = 4.87/molar mass = ?? mol H2O = 25 g/molar mass H2O = ??