A Redox Titration Lab Problem: Stoichiometry problem

Molarity of KMnO4 solution – 0.01640 M
Volume of KMnO4 required – 25.2 mL
Moles KMnO4 required – 4.1328 x 10-4 mol
Moles Fe2+ in sample – 8.2656 x 10-5 mol
Mass of Fe in sample – 4.67 x 10-3 g

Mass of sample = 1.03 g

I got the value for Moles of Fe2+ because the ratio between KMnO4 and Fe2+ is 2.

What is the Percentage of Fe in sample?


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