A fish uses a swim bladder to change its density so it is equal to that of water, enabling it to…
A fish uses a swim bladder to change its density so it is equal to that of water, enabling it to remain suspended under water. If a fish has an average density of 1090kg/m3 and mass 16.5 g with the bladder completely deflated, to what volume must the fish inflate the swim bladder in order to remain suspended in seawater of density1060 kg/m3?
My Answer: (is it right? I plugged in my answer and web assign said it was incorrect)
The volume of the fish with the swim bladder completely deflated = 0.0165kg / 1090kg/m^3 = 0.000015137 m^3 = 0.0015137 cm^3
The volume of the fish if it is going to be suspended in the water needs to be 0.0165kg / 1060kg/m^3 = 0.000015566 m^3 = 0.0015566 cm^3
The difference between the two volumes is the volume to which the swim bladder must be inflated. 0.0015566 – 0.0015137 = 0.0000429 cm^3 or 4.29EE-5